12x^2-6720x+1080=0

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Solution for 12x^2-6720x+1080=0 equation:



12x^2-6720x+1080=0
a = 12; b = -6720; c = +1080;
Δ = b2-4ac
Δ = -67202-4·12·1080
Δ = 45106560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{45106560}=\sqrt{576*78310}=\sqrt{576}*\sqrt{78310}=24\sqrt{78310}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6720)-24\sqrt{78310}}{2*12}=\frac{6720-24\sqrt{78310}}{24} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6720)+24\sqrt{78310}}{2*12}=\frac{6720+24\sqrt{78310}}{24} $

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